An organic compound contains 40% carbon , 6.67% hydrogen by mass. The empirical formula of the compound will be:

C H O

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C H_{2} O

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C H_{2} O_{2}

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C H_{4} O

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Solution

The correct option is D $C H_{2} O$
For this we make a table as:

Element

%Composition

Atomic Mass

Mole Ratio

Simple Ratio

C

40.00%

12

(40/12)

(3.33/3.33)=1

H

6.67%

1

(6.67/1)

(6.667/3.33)=2

O

53.33%

16

(53.33/16)

(3.33/3.33)=1

$∴$ Formula of compound is $= C H_{2} O$

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