An organic compound decolourises bromine in $C {C l}_{4}$ and can be reduced catalytically. Also, it gives a precipitate with ammoniacal cuprous chloride. The compound can be:

{C H}_{3} - C h = C H - {C H}_{3}

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{C H}_{3} {C H}_{2} C \equiv C H

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{C H}_{3} C H = {C H}_{2}

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C H_{3} C | C H_{3} = C H_{2}

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Solution

The correct option is B ${C H}_{3} {C H}_{2} C \equiv C H$
Answer $B .$
The organic compound decolorises bromine in $C C l_{4}$ . Hence it is unsaturated compound, that is, it can be either alkene or alkyne.
Since, the given compound gives a precipitate with ammonical cuprous chloride, it should be an alkyne as alkenes do not react with ammonical cuprous chloride.
$∴$ The compound is $C H_{3} C H_{2} C \equiv C H .$

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