Question

An organic compound having molecular formula $C_2{H}_{6}O$ under goes oxidation with $\frac{K_{2}C{r}_2{O}_7}{H_{2}S{O}_4}$ to produce X which contains $40\%$ carbon, $6.7\%$ hydrogen and $53.3\%$ oxygen. The molecular formula of the compound X is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

$C_2{H}_{5}OH\stackrel{K_{2}C{r}_2{O}_7/H_{2}S{O}_4}{\to }C{H}_{3}COOH\%C=\frac{24}{60}\times 100=40\%,\%H=\frac{4}{60}\times 100=6.7\%,\%O=\frac{32}{60}\times =53.3\%$