An organic compound with molecular formula $C_{4} H_{10} O$ does not react with sodium . With excess of HI it gives only one type of alkyl halide. The compound is:

C_{2} H_{5} O C_{2} H_{5}

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C H_{3} C | O C H_{3} H C H_{3}

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C H_{3} C H_{2} C H_{2} O C H_{3}

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C H_{3} C H_{2} C H_{2} C H_{2} O H

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Solution

The correct option is A $C_{2} H_{5} O C_{2} H_{5}$
$C_{4} H_{10} O$ can have two structures :

$C H_{3} C H_{2} C H_{2} C H_{2} O H$ and $C_{2} H_{5} O C_{2} H_{5}$ .

Since it does not react with Na metal, it can not be an alcohol.

$C_{2} H_{5} O C_{2} H_{5} + H e x c e s s I \to 2 C_{2} H_{5} I + H_{2} O$

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An organic compound with molecular formula C4H10O does not react with sodium . With excess of HI it gives only one type of alkyl halide. The compound is:

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An organic compound with molecular formula $C_{4} H_{10} O$ does not react with sodium . With excess of HI it gives only one type of alkyl halide. The compound is: