An organic compound with vapour density = 94 contains C = 12.67%, H = 2.13% and Br = 85.11%. Find the molecular formula.

[Atomic mass: C = 12, H = 1, Br = 80]

CH₄Br₂

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C₂H₂Br₂

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C₂H₄Br₂

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C₂H₄Br

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C₂H₂Br₃

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Solution

The correct option is C
C₂H₄Br₂

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Similar questions

An organic compound with vapour density = 94 contains C = 12.67%, H = 2.13%, and Br = 85.11%. Find the molecular formula.
[Atomic mass: C = 12, H = 1, Br = 80]

An organic compound has the following percentage composition: C = 12.76%, H = 2.13%, Br = 85.11%. The vapour density of the compound is 94. Find out its molecular formula [C = 12, H = 1, Br = 80].

(a)

(i) Calculate the volume of 320 of $S O_{2}$ at STP. (Atomic mass : S = 32 and O = 16).
(ii) State Gay-Lussac's law of combining volume
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane $(C_{3} H_{8})$ (Atomic mass; C = 12, 0 = 16, H = 1, Molar volume $- 22.4 d m^{3}$

(b)

(i) An organic compound with vapour density = 94 contains
C = 12.67% H = 2.13 % and Br = 85.11% Find the molecular formula.
[Atomic mass ; C = 12, H = 1, Br = 80]
(ii) Calculate the mass of
(1) $10^{22}$ Atoms of sulphur.
(2) 0.1 mole of carbon dioxide.
[Atomic mass; S = 32, C = 12 and O = 16 and Avogadro's number $= 6 \times 10^{23}$

Q. An inorganic compound contains Carbon

12.6 %

, Hydrogen

2.13 %

and Bromine

85.11 %

. Determine the empirical formula of the compound.

[C = 12, H = 1, B r = 80]

A compound has an empirical formula of C₂HBr. If the molar mass of the compound is 314.7 g/mol, what is the molecular formula of the compound? (Atomic mass of Br = 80g/mol)

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An organic compound with vapour density = 94 contains C = 12.67%, H = 2.13% and Br = 85.11%. Find the molecular formula. [Atomic mass: C = 12, H = 1, Br = 80]

The correct option is C C2H4Br2

An organic compound with vapour density = 94 contains C = 12.67%, H = 2.13% and Br = 85.11%. Find the molecular formula.

[Atomic mass: C = 12, H = 1, Br = 80]

The correct option is C
C₂H₄Br₂