An organic monobasic acid contains $18.6 %$ carbon, $1.55 %$ hydrogen and $55.04 %$ chlorine its molecular mass is $129$ .calculate its molecular formula.

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Solution

The sum of the percentage of carbon, hydrogen, and chlorine is not 100 %

Hence the rest of the part of the compound is oxygen

percentage of oxygen $= 100 - (18.6 + 1.55 + 55.04) = 24.81$

Simplest ratio $= 1 : 1 : 1 : 1$

Hence empirical formula $= C H C I O$

Empiraical formula weight $= 12 \times 1 + 1 \times 1 + 35.5 \times 1 + 16 \times 1 = 64.5$

$\frac{m o l e c u l a r m a s s}{e m p i r i c a l m a s s} = \frac{129}{64.5} = 2$

Therefore molecular formula $= n \times (E m p i r i c a l f o r m u l a)$

Molecular formula $= 2 \times (C H C I O)$

Molecular formula $C_{2} H_{2} C l_{2} O_{2}$

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An organic monobasic acid contains 18.6% carbon, 1.55% hydrogen and 55.04% chlorine its molecular mass is 129 .calculate its molecular formula.

An organic monobasic acid contains $18.6 %$ carbon, $1.55 %$ hydrogen and $55.04 %$ chlorine its molecular mass is $129$ .calculate its molecular formula.