Question

An ornament piece is made of gold and copper.Its total weight is $96$gms.If $\frac{1}{12}$ of the ornament is copper.Find the weight of gold in it.

Answer 1

Total weight$=96$g

Weight of copper$=\frac{1}{12}$ of $96$

$=\frac{1}{12}\times 96=8$gms

$\therefore$Weight of gold$=$Total weight$-$Weight of copper$=96-8=88$gms