An ornament weighing $36 g$ in air, weighs only $34 g$ in water. Assuming that some copper is mixed with gold to prepare the ornament. Find the amount of copper in it. The specific gravity of gold is $19 \cdot 3$ and that of copper is $8 \cdot 9$ .

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Solution

Density of ornament = $\frac{36}{36 - 34} = 18$
So, $18 = \frac{19.3 (V - x) + 8.9 x}{V}$
$18 V = 19.3 V - 19.3 x + 8.9 x$
$10.4 x = 1.3 V$
$x = \frac{1.3 V}{10.4} \Rightarrow x = \frac{V}{8}$

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Similar questions

Q. An ornament weighing

36 g

in air weighs only

34 g

in water. Assuming that some coppers is mixed with gold to prepare the ornament, find the amount of copper in it. Specific gravity of gold is

19.3

and that of copper is

8.9

An ornament weighing 36g in air, weighs only 34 g in water. Assuming that some copper is mixed with gold to prepare the ornament, find the amount of copper in it. Specific gravity of gold is 19.3 and that of copper is 8.9.

plz help me understand the answer clearly.

Q. An ornament weighing

36

g in air weighs only

34

g in water. Assuming that some copper is mixed with gold to prepare the ornament, find the amount of copper in it. Specific gravity of gold is

19.3

and that of copper is

8.9

I was unable to understand the previously answered question

so plz sir/madam, could you do it on a paper.......it would be helpful

Q. An ornament weighing 150 g in air weight only 76 g in water. Assuming that some copper is mixed with gold to prepare the ornament. The amount of copper in it specific gravity of gold is 20 and that of copper is 10.

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An ornament weighing 36 g in air, weighs only 34 g in water. Assuming that some copper is mixed with gold to prepare the ornament. Find the amount of copper in it. The specific gravity of gold is 19⋅3 and that of copper is 8⋅9.

Density of ornament = 3636−34=18So, 18=19.3(V−x)+8.9xV 18V=19.3V−19.3x+8.9x 10.4x=1.3V x=1.3V10.4⇒x=V8

An ornament weighing $36 g$ in air, weighs only $34 g$ in water. Assuming that some copper is mixed with gold to prepare the ornament. Find the amount of copper in it. The specific gravity of gold is $19 \cdot 3$ and that of copper is $8 \cdot 9$ .

Density of ornament = $\frac{36}{36 - 34} = 18$
So, $18 = \frac{19.3 (V - x) + 8.9 x}{V}$
$18 V = 19.3 V - 19.3 x + 8.9 x$
$10.4 x = 1.3 V$
$x = \frac{1.3 V}{10.4} \Rightarrow x = \frac{V}{8}$