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Question

An overhead line 300 km long and having surge inpedance loading of 100Ω. The line is open circuited at the receiving end and voltage of 500V is applied to the other end. Calculate the sending end voltage and current after 0.002 sec

A
500 V, -5A
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B
1000 V, +5A
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C
500 V, +5A
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D
500 V, -10A
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Solution

The correct option is A 500 V, -5A
Incident voltage V = 500 V

Incident current I=VZc=500100=5A

Time taken to reach 300 km

T=300km3×105km/sec=0.001 sec

After 2T = 0.002 sec, voltage and current at sending end side are
Vs=V=500 V
Is=I=5A

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