An ox is tied to a pole situated at the center of a field, with a 10 m long rope. The ox moves keeping the rope tight. Find the area of the ground swept by the rope.( Use $π = 3.14$ )

31.4 m^{2}

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614 m^{2}

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314 m^{2}

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416 m^{2}

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Solution

The correct option is C $314 m^{2}$
The area swept will be equal to the area of circle which can be drawn taking pole as centre and radius as length of rope.

Area of circle $= π r^{2}$

= $3.14 \times 10^{2}$ = 314 $m^{2}$ .

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An ox is tied to a pole situated at the center of a field, with a 10 m long rope. The ox moves keeping the rope tight. Find the area of the ground swept by the rope.( Use π=3.14)

The correct option is C 314 m2The area swept will be equal to the area of circle which can be drawn taking pole as centre and radius as length of rope. Area of circle =πr2 = 3.14×102 = 314 m2.

An ox is tied to a pole situated at the center of a field, with a 10 m long rope. The ox moves keeping the rope tight. Find the area of the ground swept by the rope.( Use $π = 3.14$ )

The correct option is C $314 m^{2}$
The area swept will be equal to the area of circle which can be drawn taking pole as centre and radius as length of rope.

Area of circle $= π r^{2}$

= $3.14 \times 10^{2}$ = 314 $m^{2}$ .