Question

An oxide of iodine ($I=127$) contains $25.4$ g of iodine for $8$ g of oxygen. Its formula will be :

• A. $I_2{O}_3$
• B. $I_{2}O$
• C. $I_2{O}_5$
• D. $I_2{O}_7$

Answer 1

The correct option is C $I_2{O}_5$

Given, $25.4$ g iodine combines with $8$ g oxygen.
Therefore, $254$ g iodine binds with $80$ g oxygen.
The ratio of moles $I:O=2:5$
So, oxide is $I_2{O}_5$.