Question

An Oxide of iodine $(l=127)$ contains $25.4g$ of iodine for $8g$ of oxygen. Its formula could :

• A. $I_2{O}_3$
• B. $I_{2}O$
• C. $I_2{O}_5$
• D. $I_2{O}_7$

Answer 1

Answer: (C)

$I_2{O}_5$

Moles of $I$ = given mass/molar mass

= 25.4/127

= 0.2 mole

mole of $O$= given mass/ molar mass

= 8/16

=1/2

=0.5

Ratio $I,O$ = 2:5

So the molecular formula of the compound is $I_2{O}_5$. So the option C is correct.