An oxide of metal M has 40% by mass of oxygen. Metal M has atomic mass of 24. The empirical formula of the oxide :

M_{2} O

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M_{2} O_{3}

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M O

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M_{3} O_{4}

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Solution

The correct option is B $M O$
Ratio of mass of atom
M : O
60 : 40

Ratio of moles
Moles : $\frac{60}{24} : \frac{40}{16}$
$= 1 : 1$
The formula of the compound is MO.

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Similar questions

An oxide of metal M has 40% by mass of oxygen. Metal M has relative atomic mass of 24g/mol. The empirical formula of the oxide is:

g m o l^{- 1}

g m o l^{- 1}

M_{2} O_{3}

H_{2}

M_{2} O_{3}

H_{2}

27.6 % a n d 30.0 %

M_{3}

O_{4}

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