Question

an oxide of metal m has 40% by mass of oxygen. metal m has atomic mass of 24 the empircalformula of oxide is

Answer 1

Dear Student,

$$\begin{gathered} 40\%\mathrm{by}\mathrm{mass}\mathrm{oxygen}\mathrm{means}40\mathrm{g}\mathrm{of}\mathrm{oxygen} \\ \mathrm{So},\mathrm{amount}\mathrm{of}\mathrm{metal}\mathrm{in}\mathrm{metal}\mathrm{oxide}=60\mathrm{g} \\ \mathrm{Now},\mathrm{The}\mathrm{empirical}\mathrm{formula}\mathrm{can}\mathrm{be}\mathrm{given}\mathrm{as}\frac{40}{16}:\frac{60}{24}=2.5:2.5=1:1 \\ \mathrm{Therefore},\mathrm{the}\mathrm{empirical}\mathrm{formula}\mathrm{is}\mathrm{MO} \end{gathered}$$