An oxide of metal M has 47% by mass of oxygen metal M has atomic mass of 24 the empirical formula of its oxide is

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$47 % b y m a s s o x y g e n m e a n s 47 g o f o x y g e n S o, a m o u n t o f m e t a l i n m e t a l o x i d e = 53 g N o w, T h e e m p i r i c a l f o r m u l a c a n b e g i v e n a s \frac{47}{16} : \frac{53}{24} = 2.9 : 2.2 = 1.3 : 1 = 1.3 \times 3 : 1 \times 3 = 3.9 : 3 T h e r e f o r e, t h e e m p i r i c a l f o r m u l a i s M_{4} O_{3}$

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An oxide of metal M has 40% by mass of oxygen. Metal M has relative atomic mass of 24g/mol. The empirical formula of the oxide is:

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