Question

An oxide of nitrogen has the percentage composition: N = 25.94 and O = 74.06. Calculate the empirical formula of the compound.

Answer 1

Let us consider a sample containing $100$ $g$ $NxOy$

For $N\Rightarrow x\times 14=\frac{100\times 25.94}{100}$

$\Rightarrow x=1.85$

For $O\Rightarrow y\times 16=\frac{100\times 74.09}{100}$

$\Rightarrow y=4.63$

So, $N_{1.85}{O}_{4.63}$$\Rightarrow N_2{O}_5$ (Empirical Formula)