An oxide which gives $H_{2} O_{2}$ on treatment with a dilute acid is:

P b O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T i O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $N a_{2} O_{2}$
Sodium peroxide reacts with acids to give hydrogen peroxide.
$N a_{2} O_{2} + H_{2} S O_{4} \to N a_{2} S O_{4} + H_{2} O_{2}$

Suggest Corrections

Similar questions

H_{2} O_{2}

(H_{2} O_{2})

(H_{2} {S O}_{4})

H_{2} O_{2}

The oxide that gives hydrogen peroxide ( $H_{2} O_{2}$ ) on the treatment with a dilute acid ( $H_{2} S O_{4}$ ) is

H_{2} O_{2}

H_{2} S O_{4}

Join BYJU'S Learning Program