An oxy acid contains three hydrogen atoms, one phosphorus atom and four oxygen atoms. Write the formula of the compound formed by the negative radical of the given acid with ammonium ion.

(N H_{4})_{2} P O_{4}

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N H_{4} P O_{3}

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M H_{4} P O_{3}

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(N H_{4})_{3} P O_{4}

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Solution

The correct option is D $(N H_{4})_{3} P O_{4}$
The acid is $H_{3} P O_{4}$ , which reacts with $N H_{4}^{+ 1}$ ion to form $(N H_{4})_{3} P O_{4}$ .The balanced equation for such reaction can be written as:
$H_{3} P O_{4} + 3 N H_{4} O H \to (N H_{4})_{3} P O_{4} + 3 H_{2} O$

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Write a chemical formula for a molecule that contains three Hydrogen atoms (H), one Phosphorus (P), and four Oxygens (O).

M (O H), M (O H)_{2}

M (O H)_{3}

A sample of ammonium phosphate, $(N H_{4})_{3} P O_{4}$ , contains 6 moles of hydrogen atoms. The number of moles of oxygen atoms in the sample is :

(N H_{4})_{3} P O_{4}

3.18 m o l

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