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Shear Strain

An RCC beam o...

Question

An RCC beam of width $250 m m$ and effective depth $450 m m$ is subjected to a factored shear force of $60 k N$ . The grade of materials used are $M 20$ and $F e 415$ . The concrete shear strength is $0.8 N / m m^{2}$ . The spacing (in mm, correct upto two decimal place) of $8 m m$ dia two legged stirrups is ___.
300

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Solution

The correct option is A 300
Nominal shear stress $= \frac{V_{u}}{b d}$
$= \frac{60 \times 1000}{250 \times 450} = 0.533 N / m m^{2} < 0.8 N / m m^{2}$
$∴$ Minimum shear reinforcement is to be provided.
$\frac{A_{s v}}{b S_{v}} \geq \frac{0.4}{0.87 f_{y}}$
$S_{v} \leq \frac{0.87 f_{y} A_{s v}}{0.4 b}$
$\leq \frac{0.87 \times 415 \times (2 \times \frac{π}{4} \times 8^{2})}{0.4 \times 250}$
$\leq 362.97 m m$
Maximum spacing allowed $= m i n (300 m m$ or $0.75 d)$
$= m i n (300 m m$ or $0.75 \times 450) = 300 m m$
$∴$ Spacing of stirrups provided $= 300 m m$

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