An RLC circuit has $f_{1}$ and $f_{2}$ as the half power frequency and $f_{0}$ as tthe resonant frequency. The Q factor of the circuit is given by:

\frac{f_{1} + f_{2}}{2 f_{0}}

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\frac{f_{1} - f_{0}}{f_{2} - f_{0}}

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\frac{f_{0}}{f_{1} - f_{2}}

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\frac{f_{1} - f_{2}}{f_{0}}

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Solution

The correct option is C $\frac{f_{0}}{f_{1} - f_{2}}$
Q factor of a resonating circuit is defined by the ratio of frequency of resonance to bandwidth of the circuit. Also the bandwidth is the difference between half power frequencies.

$Q = \frac{f_{0}}{B W}$ where $B W = f_{1} - f_{2}$

$Q = \frac{f_{0}}{f_{1} - f_{2}}$

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Similar questions

f (x) = 2^{x}

f (0), f (1), f (2) . . . . .

= l + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h

The h in the formula

Mode=I+ $(\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}})$ $\times$ h

stands for class width.

f (x) = x^{3} + x^{2} f^{'} (1) + x f^{''} (2) + f^{'''} (3)

x ϵ R

f_{0}

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