An rms voltage of 110 V is applied across a series circuit having a resistance 11 - and an impedance 22 - The power consumed is

We know that power in an AC circuit is given by P=V_rmsI_rmscos ϕ ⇒ P=V_rmsV_rms/ZR/Z ⇒ P=V_rms^2R/Z^2 Putting all the values we get P=110×110×11/22×22=275 W ...

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Standard XIII

Physics

Power

An rms voltag...

Question

An rms voltage of $110 V$ is applied across a series circuit having a resistance $11 Ω$ and an impedance $22 Ω$ . The power consumed is

275 W

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366 W

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550 W

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1100 W

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Solution

The correct option is A $275 W$
We know that power in an AC circuit is given by
$P = V_{r m s} I_{r m s} c o s ϕ \Rightarrow P = V_{r m s} \frac{V_{r m s}}{Z} \frac{R}{Z} \Rightarrow P = \frac{V_{r m s}^{2} R}{Z^{2}}$
Putting all the values we get
$P = \frac{110 \times 110 \times 11}{22 \times 22} = 275 W$

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An rms voltage of 110 V is applied across a series circuit having a resistance 11 Ω and an impedance 22 Ω. The power consumed is

The correct option is A 275 WWe know that power in an AC circuit is given by P=VrmsIrmscos ϕ⇒P=VrmsVrmsZRZ⇒P=V2rmsRZ2 Putting all the values we get P=110×110×1122×22=275 W

An rms voltage of $110 V$ is applied across a series circuit having a resistance $11 Ω$ and an impedance $22 Ω$ . The power consumed is