An series LCR circuit with voltage drop across L,C and R 10V each if the resistance is reduced to half then what is the voltage across each?

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Solution

Dear Student,

$l e t t h e r e a c \tan c e b e X l a n d X c l e t t h e c u r r e n t b e i 10 = i R = i X l = i X c R = X l = X c \sin c e X l = X c t h e c i r c u i t i s a r e s o n a t i n g c i r c u i t . i f t h e R i s h a l v e d t h e n c u r r e n t b e c o m e s d o u b l e . t h e n v o l t a g e a c r o s s R w i l l r e m a i n 10 v v o l t a g e a c r o s s L a n d C w i l l b e c o m e d o u b l e t h a t i s 20 v R e g a r d s$

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An series LCR circuit with voltage drop across L,C and R 10V each if the resistance is reduced to half then what is the voltage across each?

Dear Student, let the reactance be Xl and Xclet the current be i10=iR=iXl=iXcR=Xl=Xcsince Xl=Xcthe circuit is a resonating circuit.if the R is halved then current becomes double .then voltage across R will remain 10 v voltage across L and C will become double that is 20 v Regards