An tetrahedron has 4 faces and 6 edges. How many vertices does it have?

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Solution

The correct option is C 4
$V - E + F = 2$
Where
$V$ = number of vertices = ?
$E$ = number of edges = $6$
$F$ = number of faces = $4$
$V - 6 + 4 = 2$
$V - 2 = 2$
$V = 4$

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