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Question

An AC source rated 100 V (rms) supplies a current of 10 A (rms) to a circuit. The average power delivered by the source

A
must be 1000 W
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B
may be 1000 W
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C
may be greater than 1000 W
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D
may be less than 1000 W
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Solution

The correct option is D may be less than 1000 W
The average power delivered by the source is given by:

Pavg=VrmsIrmscos ϕ

Where cosϕ is the power factor of the circuit.

Given, Vrms=100 V and Irms=10 A

Pavg=100×10cosϕ=1000cosϕ

The value of cosϕ lies between [1, 1].

Therefore, power delivered by the source would be either equal to 1000 W or less than 1000 W depending on the elements connected in the circuit.

Hence, options (B) and (D) are the correct answers.
Why this question :
This question tests the basic understanding of the power factor of a circuit.

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