An unbanked curve has a radius of $60 m$ . The maximum speed at which a car can make a turn if the coefficient of static friction is $0.75$ , is

2.1 m / s

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14 m / s

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21 m / s

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7 m / s

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Solution

The correct option is C $21 m / s$
$\begin{matrix} tan θ = μ = 0.75 \frac{V^{2}}{r g} = tan θ \Rightarrow V^{2} = r g \times 0.75 V = \sqrt{60 \times 9.8 \times 0.75} = 21 m / s \end{matrix}$

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An unbanked curve has a radius of 60m. The maximum speed at which a car can make a turn if the coefficient of static friction is 0.75, is

The correct option is C 21m/stanθ=μ=0.75V2rg=tanθ⇒V2=rg×0.75V=√60×9.8×0.75=21m/s

An unbanked curve has a radius of $60 m$ . The maximum speed at which a car can make a turn if the coefficient of static friction is $0.75$ , is

The correct option is C $21 m / s$
$\begin{matrix} tan θ = μ = 0.75 \frac{V^{2}}{r g} = tan θ \Rightarrow V^{2} = r g \times 0.75 V = \sqrt{60 \times 9.8 \times 0.75} = 21 m / s \end{matrix}$