Question

An unbiased dice is rolled twice, what is the probability of not getting a 2 in anyone of the two rolls ?

Answer 1

P(getting a 2) = 1/6

So, P(not getting a 2) = 1- 1/6 = 5/6

Thus, P(not getting a 2 in 2 rolls of an unbiased dice) = $\frac{5}{6}\times \frac{5}{6}=\frac{25}{36}$