Question

An unbiased die is thrown once. What is the probability of getting a number less than $5$?

Answer 1

When the die is thrown once, the possible outcomes are $1,2,3,4,5,6$ i.e., totally $6$ out comes.
Let $E$ be the event of getting a number less than $5$. Then the favourable outcomes are $1,2,3,4$; i.e., $4$ outcomes.
Therefore, probability of getting a number less than $5$ is
$P\left(E\right)=\frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}=\frac{4}{6}=\frac{2}{3}$.