Question

An unbiased die is thrown.What is the probability of getting a multiple of $3$.

Answer 1

In a single throw of an unbiased dice, we get the outcomes as $\{1,2,3,4,5,6\}$

So, exhaustive number of cases $=6$

A multiple of $3$ is obtained if the outcome is $3$ or $6$

So, no. of favorable outcomes $=2$

$\therefore$ Required probability $=\frac{2}{6}=\frac{1}{3}$.