Question

An unbiased die is tossed. What is the probability of getting a multiple of 3?

• A. $\frac{2}{3}$
• B. $\frac{1}{3}$
• C. $\frac{1}{6}$
• D. $\frac{1}{2}$

Answer 1

The correct option is B $\frac{1}{3}$

Whenn an unbiased dice is tossed, total no. of outcomes = 6
i.e., 1, 2, 3, 4, 5, 6
Favourable outcomes = 2,
i.e, multiple of 3 (3, 6)

$\therefore$ P(multiples of 3) $=\frac{FavourableOutcomes}{TotalOutcomes}=$$\frac{2}{6}=$$\frac{1}{3}$