An unpolarised beam of intensity $I_{0}$ falls on a polaroid at an angle of $45^{0}$ . The intensity of the emergent light is

\frac{I_{0}}{2}

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I_{0}

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\frac{I_{0}}{4}

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Zero

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Solution

The correct option is A $\frac{I_{0}}{2}$
$I = I_{o} c o s^{2} ω t$
As the angle of incidence is $45^{0}$ so $c o s^{2} 45^{0} = 1 / 2$
Hence $I_{a v} = \frac{I_{o}}{2}$

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As the angle of incidence is $45^{0}$ so $c o s^{2} 45^{0} = 1 / 2$
Hence $I_{a v} = \frac{I_{o}}{2}$