Question

An unpolarized light of intensity $I_0$ is passed through three polarizers. Polarizing angle between 1st and 3rd polarizer is ${90}^{\circ }$ and that between 1st and 2nd polarizer is ${30}^{\circ }$. If intensity of light after 3rd polarizer is $\frac{x{I}_0}{8y}$ then $x+y$ is

Answer 1

So after comparing $\frac{3I_0}{32}$ with $\frac{x{I}_0}{8y}$,
We get $x=3,y=4\Rightarrow x+y=7$