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Standard XII

Mathematics

Independent Events

An urn contai...

Question

An urn contains $4$ red and $7$ blue balls. Find the probability of getting Blue balls

\frac{7}{11}

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\frac{9}{11}

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\frac{5}{11}

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\frac{3}{11}

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Solution

The correct option is A $\frac{7}{11}$

No. of red balls $= 4$

No. of Blue balls $= 7$

Total no .of balls $= 4 + 7 = 11$

Probability $= \frac{7}{11}$

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An urn contains 4 red and 7 blue balls. Find the probability of getting Blue balls

The correct option is A 711No. of red balls =4No. of Blue balls =7Total no .of balls =4+7=11Probability =711

An urn contains $4$ red and $7$ blue balls. Find the probability of getting Blue balls

The correct option is A $\frac{7}{11}$

No. of red balls $= 4$

No. of Blue balls $= 7$

Total no .of balls $= 4 + 7 = 11$

Probability $= \frac{7}{11}$