An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. If the probability of getting 2 red balls is P(A), find 121×P(A).
Probability of drawing a red ball in the first time is number of red ballstotal number of balls=711
After replacement, number of red balls =7 and number of blue balls remains 4.
Probability of drawing a red ball in the second chance =711
∴P(A)=711×711=49121
⇒ Answer = P(A)×121=49