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Question

An urn contains 7 red and 4 blue balls. Two balls are drawn at random with replacement. If the probability of getting 2 red balls is P(A), find 121×P(A).

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Solution

Probability of drawing a red ball in the first time is number of red ballstotal number of balls=711

After replacement, number of red balls =7 and number of blue balls remains 4.

Probability of drawing a red ball in the second chance =711

P(A)=711×711=49121

Answer = P(A)×121=49


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