The correct option is A 3.2
X molal defines that X moles are present in 1Kg of benzene
Hence mole fraction of solute is given by
MoleFraction=NumberofmolesofsoluteNumberofmolesofsolute+Numberofmolesofsolvent
Molefraction=XX+100078
Molefraction=XX+12.82=0.2
X=0.2X+12.82×0.2
X=3.2