An X-ray beam of wavelength $1.0 ˚ A$ is incident on a crystal of lattice spacing $2.8 ˚ A$ . The value of Bragg angle for first order of diffraction is :

{17.8}^{o}

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{10.3}^{o}

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30^{o}

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45^{o}

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Solution

The correct option is D ${17.8}^{o}$
The Bragg’s Law of diffraction is given as

$2 d sin θ = n λ$

By substituting the values given in the above equation we get

$2 \times 2.8 \times 10^{10} sin θ = 1 \times 10^{10} m$

The value of the angle is

$θ = {sin}^{- 1} (\frac{1}{5.6})$

Hence the angle is ${17.8}^{\circ}$

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An X-ray beam of wavelength 1.0˚A is incident on a crystal of lattice spacing 2.8˚A . The value of Bragg angle for first order of diffraction is :

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