An X-ray tube operates at 20 kV. A particular electron loses 5% of its kinetic energy to emit an X-ray photon at the first collision. What is the wavelength corresponding to this photon? Given that Planck's constant $= 4.14 \times 10^{- 15} e V s$ .

1.54 nm

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2.32 nm

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0.68 nm

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1.24 nm

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Solution

The correct option is D
1.24 nm

Kinetic energy of the electron, $K = 20 \times 10^{3} e V$
Energy of photon, $E = 0.05 K = 10^{3} e V$
Now, $\frac{h c}{λ} = 10^{3} \Rightarrow λ = \frac{4.14 \times 10^{- 15} \times 3 \times 10^{8}}{10^{3}} = 1.24 n m$
Hence, the correct choice is (d).

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Similar questions

An X-ray tube operates at 20 kV. A particular electron loses 5% of its kinetic energy to emit an X-ray photon at the first collision. What is the wavelength corresponding to this photon? Given that Planck's constant $= 4.14 \times 10^{- 15} e V s$ .

Q. An

X

-ray tube operates at

20 kV .

A particular electron loses

5 %

of its kinetic energy to emit an

X

-ray photon at the first collision. Find the wavelength corresponding to this photon.

Q. An X-ray tube operates at 40 kV. Suppose the electrons convert 70% its energy into a photon in each collision. Find the lowest 3 wavelength emitted.

Q. An X-ray tube operates at

40 kV

. Suppose the electron converts

70 %

of its energy into a photon at each collision. Find the lowest three wavelengths emitted from the tube. Neglect the energy imparted to the atom with which the electron collides.

(h c = 1242 eV-nm)

An X-ray tube operates at 40 kV. Suppose the electron converts 70 % of its energy into a photon at each collision. Find the lowest three wavelengths emitted from the tube. Neglect the energy imparted to the atom with which the electron collides.

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An X-ray tube operates at 20 kV. A particular electron loses 5% of its kinetic energy to emit an X-ray photon at the first collision. What is the wavelength corresponding to this photon? Given that Planck's constant =4.14×10−15 eVs.

The correct option is D 1.24 nm Kinetic energy of the electron, K=20×103 eV Energy of photon, E=0.05K=103 eV Now, hcλ=103⇒λ=4.14×10−15×3×108103=1.24 nm Hence, the correct choice is (d).

An X-ray tube operates at 20 kV. A particular electron loses 5% of its kinetic energy to emit an X-ray photon at the first collision. What is the wavelength corresponding to this photon? Given that Planck's constant $= 4.14 \times 10^{- 15} e V s$ .

The correct option is D
1.24 nm

Kinetic energy of the electron, $K = 20 \times 10^{3} e V$
Energy of photon, $E = 0.05 K = 10^{3} e V$
Now, $\frac{h c}{λ} = 10^{3} \Rightarrow λ = \frac{4.14 \times 10^{- 15} \times 3 \times 10^{8}}{10^{3}} = 1.24 n m$
Hence, the correct choice is (d).