Question

An X-ray tube produces a continuous spectrum of radiation with its short wavelength end at 0.40$A^0$. Then the maximum energy of the photon of the emitted radiation.

($h=6.63\times {10}^{-34}Js$ and $c=3\times {10}^8$ m/s)

• A. $4.9725\times {10}^{-15}J$
• B. $6.28\times {10}^{-15}J$
• C. $3.15\times {10}^{-15}J$
• D. $2.98\times {10}^{-15}J$

Answer 1

Answer: (A)

$4.9725\times {10}^{-15}J$

${\lambda }_{cutoff}=\frac{hc}{E}$
$E_{max}=\frac{20\times {10}^{-26}}{0.4\times {10}^{-10}}$
$=4.9725\times {10}^{-15}J$

So, the answer is option (A).