Question

An X-ray tube produces a continuous spectrum of radiation with its short-wavelength end at 0.33 angstrom. What is the maximum energy of a photon in the radiation? Given Planck's constant $=6.6\times {10}^{-34}Js$.

• A. 35 keV
• B. 37.5 keV
• C. 40 keV
• D. 42.5 keV

Answer 1

The correct option is B 37.5 keV

We know that, $E_{max}=\frac{hc}{{\lambda }_{min}}=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{0.33\times {10}^{-10}}=6\times {10}^{-15}J=37.5keV$
Hence, the correct choice is (b).