According to Moseleys equation for Kα radiation
1λ=R(Z−1)2[112−122] where λ= wavelength of copper
Let λ1 and λ2 be the two other unknown wavelengths, then
λ1λ=(Z−1)2(Z1−1)2=0.70921.5405
Solving we get Z1=42
Similarly,
λ2λ=(28)2(Z2−1)2=1.65781.5405
Solving, we get Z2=28