Question

An $X-Y$ flip-flop, whose Characteristic Table is given below is to be implemented using a $J-K$ flip flop.

$X$	$Y$	$Q_{n+1}$
$0$	$0$	$1$
$0$	$1$	$Q_n$
$1$	$0$	${\overline{Q}}_n$
$1$	$1$	$0$

This can be done by making

Answer 1

$X-Y$ truth table

$X$	$Y$	$Q_{n+1}$
$0$	$0$	$1$
$0$	$1$	$Q_n$
$1$	$0$	${\overline{Q}}_n$
$1$	$1$	$0$

$J-K$ truth table

$X$	$Y$	$Q_{n+1}$
$0$	$0$	$Q_n$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	${\overline{Q}}_n$

Excitation table

$Q\left(t\right)$	$Q(t+1)$	J	K	X	Y
$0$	$0$	$0$	$x$	$x$	$1$
$0$	$1$	$1$	$x$	$x$	$0$
$1$	$0$	$x$	$1$	$1$	$x$
$1$	$1$	$x$	$0$	$0$	$x$

To make $(X-Y)FF$ using $(J-K)FF$,$\left(J\right)$ should be $\left(\overline{Y}\right)$ and $\left(K\right)$ should be $\left(X\right)$