Question

Analyse the following reaction and identify the product.​
$H_{2}S{O}_4$ (aq) + $Ca\left(OH{)}_2\right($aq) $\to$ ____+______

• A. X:$CaS{O}_4$, Y: $H_{2}O$
• B. X:$CaS{O}_4$, Y:$S{O}_2$
• C. X: $C{a}_{2}S{O}_4$, Y:$S{O}_2$
• D. X: $C{a}_{2}S{O}_4$, Y: $H_{2}O$

Answer 1

The correct option is A X:$CaS{O}_4$, Y: $H_{2}O$

The ions present in the aqueous medium are: $H^{+}$, $S{O}_4^2$${}^{-}$, $C{a}^2$${}^{+}$, and $O{H}^{-}$.

Now during this acid-base neutralisation reaction, the oppositely charged ions attract each other to form calcium sulphate salt and water.
The $H^{+}$ cation of the acid combines with the $O{H}^{-}$ anion of the base to form water.
The compound formed by the cation of the base and the anion of the acid is called a salt.

The overall chemical reaction will be:
$H_{2}S{O}_4$ (aq) + $Ca\left(OH{)}_2\right($aq) $\to$ $CaS{O}_4$ (aq)+$H_{2}O$ (l)