Analysis shows that FeO has a non-stoichiometric composition with formula $F e_{0.95}$ O. Give reason.

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Solution

It shows metal deficiency defect, in which some $F e^{2 +}$ irons are replaced by $F e^{3 +}$ irons. So mixture of $F e^{2 +}$ ions and $F e^{3 +}$ ions formed.

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Similar questions

FeO is found with a composition of $F e_{0.95}$ O. It ranges from $F e_{0.93}$ O to Fe_0.95O. Which type of defect is it showing here?

Why is FeO(s) not formed is stoichiometric composition ?

N i_{0.98} O

N i^{2 +}

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