Question

Analyze the given circuit in the steady state condition. Charge on the capacitor is $q_o=16\mu C$.
Find the current in each branch.

Answer 1

Here,

The circuit has two branches in which several resistors and a capacitor is connected.

The potential difference between the capacitor terminal is $=\frac{16}{4}=4V$

Lets assume the current in lower branch is $i_1$ and upper be $i_2$,

Applying Kirchhoff Voltage Law,

$0+4i_1-3i_2=4$

$0-4i_1+6i_2=4$

Adding the above two-equation,

$3i_2=8$

$i_2=\frac{8}{3}=3\left(approx\right)$

$i_1=\frac{4+3i_2}{4}=\frac{12}{4}=3$

Hence $3$ is the correct answer.