Anand and Amir ran 35 km 750 m and 28 km 90 m, respectively in two hours. Who ran more and by how many kilometers?

Open in App

Solution

$D i s \tan c e t r a v e l l e d b y A n a n d & A m i r \sin c e 1 m = \frac{1}{1000} k m 35 k m 750 m = 35 + (\frac{750}{1000}) = 35.000 + 00.750 = 35.750 k m & 28 K m 90 m = 28 + (\frac{90}{1000}) = 28.000 + 00.090 = 28.090 k m t h e r e f o r e, 35.750 > 28.090 35.750 - 28.090 07.660 H e n c e, A n a n d r a n m o r e t h a n A m i r b y 7.660 k m .$

Suggest Corrections

Similar questions

In a week, Mike ran 8 km farther than Bill, while Pete ran 1 km less than 3 times as far as Bill. If Pete ran 15 km farther than Mike, how many kilometers did Bill run?

Q. On saturday, Dan ran 0.6 km, and on sunday he ran 750 m. Which day did he run farther and by how much? (State your answer in km)

Q. In a 5 km marathon, Manish ran 2 km. If Kushagra ran

\frac{1}{2}

of the total distance of the marathon, who ran more?

Q. Two runners ran from there points and met at a common point. One ran 35 km and the other ran 77 km, what would be the length if they both would have ran in the same direction diagonally?

Q. Akhil ran 15 km in 2 hours in a marathon. How many kilometres would he run in the next 3 hours if he runs at the same speed?

Join BYJU'S Learning Program

Anand and Amir ran 35 km 750 m and 28 km 90 m, respectively in two hours. Who ran more and by how many kilometers?

DistancetravelledbyAnand&Amirsince1m=11000km35km750m=35+(7501000)=35.000+00.750=35.750km&28Km90m=28+(901000)=28.000+00.090=28.090kmtherefore,35.750>28.09035.750-28.09007.660Hence,AnandranmorethanAmirby7.660km.