Question

Andy has twice as many marbles as pandy, and sandy has half as many has Andy and pandy put together. If Andy has $75$ marbles more than Sandy. How many does each of them have

Answer 1

Let Andy has $2x$ marbles

then, Pandy has $x$ marbles and Sandy has $\frac{1}{2}(x+2x)=\frac{3x}{2}$ marbles

Now, Andy has $75$ more than Sandy

$\Rightarrow 2x=\frac{3x}{2}+75$

$\frac{x}{2}=75\Rightarrow x=150$ marbles

$2x=300$ marbles $\frac{3x}{2}=\frac{150\times 3}{2}=225$ marbles