$∠ A = ∠ E, ∠ B = ∠ D a n d A B = E D$ then by __________ congruence condition $△ A B C ≅ △ E D F$

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Solution

Given $∠ A = ∠ E, ∠ B = ∠ D a n d A B = E D$
Since in $△ A B C a n d △ E D F$
$∠ A = ∠ E (G i v e n) A B = E D (G i v e n) ∠ B = ∠ D (G i v e n)$
Therefore, by the $A S A c o n g r u e n c e$
$△ A B C ≅ △ E D F$

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∠A=∠E,∠B=∠DandAB=ED then by __________ congruence condition △ABC≅△EDF

Given ∠A=∠E,∠B=∠DandAB=EDSince in △ABCand△EDF∠A=∠E(Given)AB=ED(Given)∠B=∠D(Given)Therefore, by the ASAcongruence △ABC≅△EDF

$∠ A = ∠ E, ∠ B = ∠ D a n d A B = E D$ then by __________ congruence condition $△ A B C ≅ △ E D F$

Given $∠ A = ∠ E, ∠ B = ∠ D a n d A B = E D$
Since in $△ A B C a n d △ E D F$
$∠ A = ∠ E (G i v e n) A B = E D (G i v e n) ∠ B = ∠ D (G i v e n)$
Therefore, by the $A S A c o n g r u e n c e$
$△ A B C ≅ △ E D F$