Question

$\angle ACB$ is inscribed in arc $ACB$ of a circle with centre $O$. If $\angle ACB={65}^o$, find $m\left(arcACB\right)$.

• A. ${65}^o$
• B. ${130}^o$
• C. ${295}^o$
• D. ${230}^o$

Answer 1

Answer: (B)

${130}^o$

In question , actually $m\left(arcACB\right)$ is a misprint, $m\left(arcAB\right)$ is asked i.e. angle subtended by arc $AB$ at the centre.

Angle subtended by the arc at the circumference is $\frac{1}{2}\times$ the angle subtended at centre.

$\Rightarrow \angle AOB=2\times \angle AB$

$=2\times {65}^0$

$={130}^0$

$\therefore B)$ Answer.