Question

Angle between asymptotes of the hyperbola $3x^2-y^2=3$ is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Equations of the pair of Asymptodes is $3x^2-y^2+k$ = 0. But passes through origin

$\Rightarrow k=0$

$\therefore \text{Asymptotes are}3x^2-y^2=0$

$\therefore \text{Angle}\left(\alpha \right)\text{between}\text{them}\alpha$ = $2ta{n}^{-1}\left\{\frac{2\sqrt{0+3}}{3-1}\right\}$

$\therefore \alpha =\frac{2\pi }{3}$