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Question

Angle between the vectors 3(¯aׯb) and ¯b(¯a.¯b)¯a is

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Solution

(3(¯aׯb)).(¯b(¯a.¯a).¯a)=|(3(¯×¯))||¯b(¯a.¯b)¯b|cosP
Where P is the angle them, so.
cosP=0
So, P=π/2
Hence those are perpendicular.

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