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Byju's Answer
Standard XII
Mathematics
Definition of Vector
Angle between...
Question
Angle between the vectors
√
3
(
¯
a
×
¯
b
)
and
¯
b
−
(
¯
a
.
¯
b
)
¯
a
is
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Solution
(
√
3
(
¯
a
×
¯
b
)
)
.
(
¯
b
−
(
¯
a
.
¯
a
)
.
¯
a
)
=
|
(
√
3
(
¯
×
¯
)
)
|
|
¯
b
−
(
¯
a
.
¯
b
)
¯
b
|
cos
P
Where
P
is the angle them, so.
cos
P
=
0
So,
P
=
π
/
2
Hence those are perpendicular.
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Similar questions
Q.
If
¯
a
and
¯
b
are non-collinear unit vectors and
|
¯
a
+
¯
b
|
=
√
3
then
(
2
¯
a
+
5
¯
b
)
⋅
(
3
¯
a
−
¯
b
)
=
?
Q.
Show that the points having position vectors,
¯
a
,
¯
b
and
3
¯
a
−
2
¯
b
are colliera, where
¯
a
,
¯
b
,
¯
c
any vectors.
Q.
If
¯
a
and
¯
b
are non-collinear unit vectors and
∣
∣
¯
a
+
¯
b
∣
∣
=
√
3
then
(
2
¯
a
+
5
¯
b
)
⋅
(
3
¯
a
−
¯
b
)
=
?
Q.
Assertion :Let
¯
a
,
¯
b
,
¯
r
be the vectors such that
¯
r
+
¯
r
×
¯
a
=
¯
b
then
|
¯
r
|
2
=
(
¯
a
.
¯
b
)
2
+
∣
∣
¯
b
∣
∣
2
1
+
|
¯
a
|
2
. Reason:
¯
r
=
(
¯
a
.
¯
b
)
¯
a
+
¯
b
+
¯
a
×
¯
b
1
+
|
¯
a
|
2
.
Q.
If
√
3
¯
a
.
¯
b
=
|
¯
a
×
¯
b
|
the angle between vector
¯
a
and vector
¯
b
is:
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