Angle between the vectors -3a-b and b-a-ba is

The correct option is A #10; π2 #10; V⃗=√(3)(a⃗×b⃗) U⃗=b⃗ (a⃗ b⃗)a⃗ V⃗ U⃗=√(3)(a⃗×b⃗) (b⃗ (a⃗.b⃗)a⃗) =0 So angle between U⃗ ...

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Standard X

Mathematics

Section Formula

Angle between...

Question

Angle between the vectors $\sqrt{3} (¯ ¯ ¯ a \times ¯ ¯ b)$ and $¯ ¯ b - (¯ ¯ ¯ a . ¯ ¯ b) ¯ ¯ ¯ a$ is

\frac{π}{2}

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\frac{π}{4}

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\frac{π}{3}

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Solution

The correct option is A $\frac{π}{2}$
$\to V = \sqrt{3} (\to a \times \to b)$
$\to U = \to b - (\to a - \to b) \to a$
$\to V - \to U = \sqrt{3} (\to a \times \to b) - (\to b - (\to a . \to b) \to a)$
$= 0$
So angle between $\to U$ & $\to V$ is $\frac{π}{2}$

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Angle between the vectors √3(¯¯¯a×¯¯b) and ¯¯b−(¯¯¯a.¯¯b)¯¯¯a is

The correct option is A π2 →V=√3(→a×→b)→U=→b−(→a−→b)→a→V−→U=√3(→a×→b)−(→b−(→a.→b)→a)=0So angle between →U & →V is π2

Angle between the vectors $\sqrt{3} (¯ ¯ ¯ a \times ¯ ¯ b)$ and $¯ ¯ b - (¯ ¯ ¯ a . ¯ ¯ b) ¯ ¯ ¯ a$ is

The correct option is A $\frac{π}{2}$
$\to V = \sqrt{3} (\to a \times \to b)$
$\to U = \to b - (\to a - \to b) \to a$
$\to V - \to U = \sqrt{3} (\to a \times \to b) - (\to b - (\to a . \to b) \to a)$
$= 0$
So angle between $\to U$ & $\to V$ is $\frac{π}{2}$